A 0.020 kg bullet is shot horizontally and collides with a 1.23 kg block of wood. The bullet embeds in the block and the block slides along a horizontal surface for 1.50 m. If the coefficient of kinetic friction between the block and surface is 0.365, what was the original speed of the bullet?Can someone help me work this one?
This isn't the physics/homework section.
Goddammit.Can someone help me work this one?
This is not the physics section. However, the answer can be worked out (by YOU) observing that the kinetic energy associated with the bullet in flight must be equal to the work dissipated by the block sliding over the horizontal surface
Kinetic Energy = 1/2 m v^2
Work= F s
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