How do I work this titrate question?

Calculate the molarity of a oxalic acid solution, C2O4H2, if 50.00 mL of the oxalic acid solution is titrated with 42.12 mL of 0.09846 M KOH. Report your answer to the correct number of significant figures!





C2O4H2 (aq) + 2 KOH (aq) --%26gt; K2C2O4 (aq) + 2 H2O (l)How do I work this titrate question?
C2O4H2 (aq) + 2 KOH (aq) --%26gt; K2C2O4 (aq) + 2 H2O (l)





from the equation u can c that for every 1 mole of oxalic acid u need 2 moles of KOH.


1000ml of KOH contains 0.09846


so 42.12 ml will contain 0.09846 *42.12/1000= X


X/2 is the no. of moles in 50ml of oxalic acid.


so X*1000/(50*2)


=10X.


so 10X is the molarity of the oxalic acid.


abt the significat no. i dont remember the rules. so u better look it up sum book or the net.How do I work this titrate question?
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