This may seem like an easy math question, but can someone work this out for me and show how you did it?

The sum of three consecutive whole numbers is 450. Find the numbers.





Thanks,





KariThis may seem like an easy math question, but can someone work this out for me and show how you did it?
Let x be the smallest digit. Then (x+1) is the next consecutive digit and (x+2) is the next, and





x + (x+1) + (x+2) = 450


3x + 3 = 450


3x = 447


x = 149


x+1 = 150


x+2 = 151This may seem like an easy math question, but can someone work this out for me and show how you did it?
divide the number by 3 = 150


so you have 3 X 150 ( 150 ... 150 ... 150)


subtract 1 from one of the 150s, add it onto the other:


149....150...151 (added together = 450 agn)


:D
wel sumppl did da theoritical way while nick did it in da shortcut way.. ;-)
Divide by three and that would be the middle number which is 150 the other would be one higher (151) and one lower (149).








x = middle number


x +1 = highest number


x - 1 = lowest number.





x + x -1 +x + 1 = 450


3x = 450


x =150





x +1 = 151


x -1 = 149
149, 150, 151 I just divided 450 by 3 and then did guess and check.
x + x + 1 + x + 2 = 450


3x + 3 = 450


3x = 450 - 3


3x = 447


x = 149


149, 150, 151
149,150,151


i took 450/3=150 then take away one and add one the even each other out
Oh well, it;s quite easy.


Think that your numbers are x, x+1 and x+2


so


x+x+1+x+2 = 450


that means


3x +3 = 450


so


3x=450-3





3x = 447





-%26gt;x=149


so you have


149 150 and 151 :D
I divided by the quantity of numbers, which is 3. The average is 150. They are consecutive whole numbers, so that would be the numbers right before and after 150, until I get to three total numbers. That would be 149, 150, and 151.
Answer is: 149, 150, 151


1st number = x


2nd number = x+1


3rd number = x+2





Sum of 3 consecutive whole numbers (x+x+1+x+2) = 450.


3x+3 = 450


3x = 447


x = 149


x+1 = 150


x+2 = 151
This is an algebra problem





First you have to identify what you are trying to find. Since you have to find three consecutive numbers, you first have to find the first one.





x





Then you will have to find the second


x+1





Then you will have to find the third


x+2





When you have labeled all the numbers then you add


x+x+1+x+2=450





Then you combine like terms and you get


3x+3=450





Then you have to subtract the 3 from both sides


3x+3-3=450-3





Then you will get


3x=447





You will then divide by sides by 3


3x/3=447/3





Then you will have


x=149





So if x=149, then x+1=150, and x+2=151.
X = first number


Y = second number


Z = third number





Y = X +1


Z = Z + 2





X +Y + Z = 450





X + (X + 1) + (x + 2) = 450





3X + 3 = 450





3X = 447





X = 149


Y = 150


Z = 151
1+n(any varriable)+2+n+3+n=450


3+3n=450


3-3+3n=450-3


3n/3=447/3


n=149


1+149


2+149


3+149
Ok, so you know that the three numbers follow one right after the other. Therefore, if 'x' is the lowest number, x+2 is the highest, and x+1 is the middle number.


So, as we're looking for the sum, we're going to add these three values to find for unknown number x.


x+(x+1)+(x+2)=450.


Being an addition problem, we don't have to worry about the parentheses.


x+x+x+1+2=450, which simplifies to 450=3x+3


Next, we try to get x on its own. Remember, what is done to one side, must be done to the other!


450-3=3x+3-3, which simplifies to 3x=447.


3x/3=447/3, which is x=447/3


So, if the lowest number is 447/3, then the middle number is 447/3+1, which is 450/3. The highest number must be 447/3+2, which is 453/3.








I hope that didn't confuse you too much. And I really hope that wasn't your homework.


Good luck in Algebra!