Two standard dice are rolled. What are the odds in favor of rolling a sum of 10? How do you work this?

Hi,





The odds are 1 in 12 that you will roll a total of 10.





....1..2..3. 4 .5 .. 6


.-------------------------


1|.2..3. 4. 5. 6. . 7.|


2|.3 .4. 5. 6. 7. . 8.|


3|.4. 5. 6. 7. 8. ..9.|


4|.5. 6. 7. 8. 9. 10.|


5|.6. 7. 8.9.10. 11 |


6|.7. 8. 9 10.11.12|





In this chart of totals there are 3 tens out of 36. That's a probability of 1/12. %26lt;==ANSWER





I hope that helps!! :-)Two standard dice are rolled. What are the odds in favor of rolling a sum of 10? How do you work this?
Let's think of all the combinations that sum to 10.





Die 1 | Die 2


6 | 4


5 | 5


4 | 6





So, there's a 3/6 chance of scoring a possibly useful number on die one, and then a 1/6 chance of scoring the corresponding number one die two.





So the chance of a sum of 10 is 3/6 * 1/6 = 3/36 = 1/12.Two standard dice are rolled. What are the odds in favor of rolling a sum of 10? How do you work this?
There are 3 ways to get sum of 10: 4+6, 5+5, 6+4


There are total of 6*6 = 36 ways.





Probability = 3/36 = 1/12


Odds = 1/11


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Ideas: Odds = #favorable outcomes/#unfavorable outcomes.
There are 36 possible outcomes from rolling two dice. A sum of ten arises from 4-6, 5-5, and 6-4, and in no other way, therefore the odds are 1 in 12 that you will roll a 10.
36 possible outcomes (6*6)





You get a 10 by





4, 6


5, 5


6, 4





3/36


1/12
pi r squared is right!